Bonjour Jeanlé et tous,
Pas commode cette grille !
Voici une solution qui fait appel à cinq interdits ternaires, dont trois utilisant des conflits dérivés ternaires.
D'abord, cinq OU en marquage simple (je n'ai pas vérifié leur absolue nécessité) :
_ | a______ b______ c_____ | d___ e_____ f_____ | g______ h______ i_____ |
1 | 2l36D9ä 2L39___ ______ | ____ 1i49v_ 46d9__ | 13n4___ 1a4A___ ______ |
2 | _______ 8b9B___ ______ | 5b8B ______ 5B9b__ | 2c6C___ 2C6c___ ______ |
3 | 367á8__ 378____ 6à78__ | ____ 1I48b_ 4d6D__ | _______ _______ 1i3N4p |
4 | _______ 789____ 6789__ | ____ 5E67r8 ______ | 689____ _______ 5e9E__ |
5 | 23o678_ 23O4x78 2w4678 | ____ 5e678_ ______ | 468____ 45z67â8 4f5F__ |
6 | 6789___ _______ 4q6789 | 6B8b 678___ ______ | 1j4689u 1J467Â8 ______ |
7 | 2m8t9__ _______ ______ | 1b5B 4g9G__ ______ | 1248ã9_ 12458__ 145z9_ |
8 | 8h9H___ 1k489__ 489___ | ____ ______ 4y5b9v | _______ 1K45B8t ______ |
9 | _______ 1K247s9 2W47S9 | 1B6b 46B9__ ______ | 123N49_ 124____ 13n49_ |
b/v(9Kf) =>-9b9 (ni B=9b2, ni V=9abc8)
B/K(f8) =>-8b8 (ni b=8b2, ni k=1b8)
b/I(e3) =>-1i9 (ni B=1d9, ni i=1i3)
Q/f(4R6)-F/e(5Ki)-E/r(e4)=>Q/r =>-7c6 (ni q=4c6, ni R=7bc4)
a/i(1R3)-I/b(e3)=>a/b =>-4h8 (ni A=4h1, ni B=5h8)
Puis les ternaires :
_ | a______ b______ c_____ | d___ e_____ f_____ | g______ h______ i_____ |
1 | 2l36D9ä 2L39___ ______ | ____ 1i49v_ 46d9__ | 13n4___ 1a4A___ ______ |
2 | _______ 8b9B___ ______ | 5b8B ______ 5B9b__ | 2c6C___ 2C6c___ ______ |
3 | 367á8__ 378____ 6à78__ | ____ 1I48b_ 4d6D__ | _______ _______ 1i3N4p |
4 | _______ 789____ 6789__ | ____ 5E67r8 ______ | 689____ _______ 5e9E__ |
5 | 23o678_ 23O4x78 2w4678 | ____ 5e678_ ______ | 468____ 45z67â8 4f5F__ |
6 | 6789___ _______ 4q689_ | 6B8b 678___ ______ | 1j4689u 1J467Â8 ______ |
7 | 2m8t9__ _______ ______ | 1b5B 4g9G__ ______ | 1248ã9_ 12458__ 1I45z9 |
8 | 8h9H___ 1k49___ 48é9__ | ____ ______ 4y5b9v | _______ 1K5B8t_ ______ |
9 | _______ 1K247s_ 2W47S9 | 1B6b 46B9__ ______ | 123N49_ 124____ 3n49__ |
DERIVE TERNAIRE (q-4g6-4h6)+4g6/1h9+4h6/1h9=>Q/1h9
4g6/j(g6)-J/1h9(1Kh)=4g6/1h9
4h6/A(4Kh)-a/1h9(1Kh)=4h6/1h9
INTERDIT TERNAIRE (4b8-4c8-y)/1h9=>-1h9
4b8/k(b8)-K/1h9(1Kh)
4c8/q(4Kc)-Q/1h9(DT)
y/b(f8)-B/1h9(1L9)
--------------------------------------------------
DERIVE TERNAIRE (q-4g6-4h6)+4g6/4h9+4h6/4h9=>Q/4h9
4g6/j(g6)-J/a(1Kh)-A/4h9(4Kh)=4g6/4h9
4h6/4h9(4Kh)
INTERDIT TERNAIRE (4b8-4c8-y)/4h9=>-4h9
4b8/k(b8)-K/a(1Kh)-A/4h9(4Kh)
4c8/q(4Kc)-Q/4h9(DT)
y/4h9(4L9)
___________________________________________________
DERIVE TERNAIRE (q-4g6-4h6)+4g6/9b8+4h6/9b8=>Q/9b8
4g6/j(g6)-J/K(1Kh)-k/9b8(b8)=4g6/9b8
4h6/A(4Kh)-a/K(1Kh)-k/9b8(b8)=4h6/9b8
INTERDIT TERNAIRE (4b8-4c8-y)/9b8=>-9b8
4b8/9b8(b8)
4c8/q(4Kc)-Q/9b8(DT)
y/b(f8)-B/9b8(9Kb)
------------------------------------
INTERDIT TERNAIRE (K-B-t)/9b4=>-9b4
K/J(1Kh)-j/u(g6)-U/9b4(9R4)
B/9b4(9Kb)
t/h(8Ka)-H/Æ(9R7)-æ/9b4(9R4)
---------------------------------------
INTERDIT TERNAIRE (4b8-4c8-y)/3a1=>-3a1
4b8/k(b8)-K/I(1R9)-i/N(i3)-n/3a1(3L1)
4c8/X(4R7)-x/O(b5)-o/3a1(3Ka)
y/d(4Kf)-D/3a1(a1)
Fin par un simple interdit :
_ | a____ b_____ c____ | d_ e____ f___ | g_____ h_____ i____ |
1 | _____ ______ _____ | __ 1A49g 4g9G | ______ 1a4A__ _____ |
2 | _____ ______ _____ | __ _____ ____ | ______ ______ _____ |
3 | 3O7á8 3o78ê_ 7Q8q_ | __ 1a4A_ ____ | ______ ______ 1A4a_ |
4 | _____ 7R8r__ _____ | __ 5E7r8 ____ | 8E9e__ ______ 5e9E_ |
5 | 3o78_ 3O4Q78 _____ | __ 5e78_ ____ | ______ 47â8__ 4e5E_ |
6 | 789h_ ______ 4q89H | __ 7ë8Ë_ ____ | 1j4ì8_ 1J47Â8 _____ |
7 | _____ ______ _____ | __ 4g9G_ ____ | 1J48ã9 148Ã__ 1a49e |
8 | 8h9H_ ______ 4g8H9 | __ _____ 4G9g | ______ ______ _____ |
9 | _____ 4q7Q__ 47q9g | __ _____ ____ | 4g9G__ ______ _____ |
e/G(9L7)-g/A(e1)-a/e(i7) =>e=Faux et fin.
Cordialement.
Cenoman